From dac326b8234f698636d588c5722d3b174a800b1d Mon Sep 17 00:00:00 2001 From: "Haikun.Wang@freescale.com" Date: Thu, 9 Jul 2015 19:58:03 +0800 Subject: generic_board: Call "checkboard" even though the root node has a "model" property In case of enable CONFIG_OF_CONTROL and has a "model" property in the root node, the board special "checkboard" will not be called. Usually we show some useful version information in the function. This patch enable call "checkboard" in any case. It is not conflicting with showing "model" at the same time. For example on LS2085AQDS: Showing "model" only: Model: Freescale Layerscape 2085a QDS Board Showing "checkboard" only: Board: LS2085E-QDS, Board Arch: V1, Board version: B, boot from vBank: 4 Showing both: Model: Freescale Layerscape 2085a QDS Board Board: LS2085E-QDS, Board Arch: V1, Board version: B, boot from vBank: 4 Signed-off-by: Haikun Wang Reviewed-by: Simon Glass diff --git a/common/board_info.c b/common/board_info.c index 42d0641..4e5a1f7 100644 --- a/common/board_info.c +++ b/common/board_info.c @@ -14,8 +14,7 @@ int __weak checkboard(void) /* * If the root node of the DTB has a "model" property, show it. - * If CONFIG_OF_CONTROL is disabled or the "model" property is missing, - * fall back to checkboard(). + * Then call checkboard(). */ int show_board_info(void) { @@ -25,10 +24,8 @@ int show_board_info(void) model = fdt_getprop(gd->fdt_blob, 0, "model", NULL); - if (model) { + if (model) printf("Model: %s\n", model); - return 0; - } #endif return checkboard(); -- cgit v0.10.2