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/*
 *
 * builtin-bench-pipe.c
 *
 * pipe: Benchmark for pipe()
 *
 * Based on pipe-test-1m.c by Ingo Molnar <mingo@redhat.com>
 *  http://people.redhat.com/mingo/cfs-scheduler/tools/pipe-test-1m.c
 * Ported to perf by Hitoshi Mitake <mitake@dcl.info.waseda.ac.jp>
 *
 */

#include "../perf.h"
#include "../util/util.h"
#include "../util/parse-options.h"
#include "../builtin.h"
#include "bench.h"

#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <signal.h>
#include <sys/wait.h>
#include <linux/unistd.h>
#include <string.h>
#include <errno.h>
#include <assert.h>
#include <sys/time.h>

#define LOOPS_DEFAULT 1000000
static int loops = LOOPS_DEFAULT;
static int simple = 0;

static const struct option options[] = {
	OPT_INTEGER('l', "loop", &loops,
		    "Specify number of loops"),
	OPT_BOOLEAN('s', "simple-output", &simple,
		    "Do simple output (this maybe useful for"
		    "processing by scripts or graph tools like gnuplot)"),
	OPT_END()
};

static const char * const bench_sched_pipe_usage[] = {
	"perf bench sched pipe <options>",
	NULL
};

int bench_sched_pipe(int argc, const char **argv,
		     const char *prefix __used)
{
	int pipe_1[2], pipe_2[2];
	int m = 0, i;
	struct timeval start, stop, diff;
	unsigned long long result_usec = 0;

	/*
	 * why does "ret" exist?
	 * discarding returned value of read(), write()
	 * causes error in building environment for perf
	 */
	int ret;
	pid_t pid;

	argc = parse_options(argc, argv, options,
			     bench_sched_pipe_usage, 0);

	assert(!pipe(pipe_1));
	assert(!pipe(pipe_2));

	pid = fork();
	assert(pid >= 0);

	gettimeofday(&start, NULL);

	if (!pid) {
		for (i = 0; i < loops; i++) {
			ret = read(pipe_1[0], &m, sizeof(int));
			ret = write(pipe_2[1], &m, sizeof(int));
		}
	} else {
		for (i = 0; i < loops; i++) {
			ret = write(pipe_1[1], &m, sizeof(int));
			ret = read(pipe_2[0], &m, sizeof(int));
		}
	}

	gettimeofday(&stop, NULL);
	timersub(&stop, &start, &diff);

	if (pid)
		return 0;

	if (simple)
		printf("%lu.%03lu\n",
		       diff.tv_sec, diff.tv_usec / 1000);
	else {
		printf("(executing %d pipe operations between two tasks)\n\n",
			loops);

		result_usec = diff.tv_sec * 1000000;
		result_usec += diff.tv_usec;

		printf("\tTotal time:%lu.%03lu sec\n",
		       diff.tv_sec, diff.tv_usec / 1000);
		printf("\t\t%lf usecs/op\n",
		       (double)result_usec / (double)loops);
		printf("\t\t%d ops/sec\n",
		       (int)((double)loops /
			     ((double)result_usec / (double)1000000)));
	}

	return 0;
}