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| author | Simon Glass <sjg@chromium.org> | 2017-05-17 09:25:42 (GMT) |
|---|---|---|
| committer | Tom Rini <trini@konsulko.com> | 2017-05-22 16:45:32 (GMT) |
| commit | aed998aa34b22e818b2cd58ca7f2246716f2c3a6 (patch) | |
| tree | ae02a003bdbba0da36dc3097ffaf8e76bb670848 /README | |
| parent | 4a37cb50386a8affa2cfc68874ba88664b8ceca2 (diff) | |
| download | u-boot-fsl-qoriq-aed998aa34b22e818b2cd58ca7f2246716f2c3a6.tar.xz | |
Convert CONFIG_LZMA to Kconfig
This converts the following to Kconfig:
CONFIG_LZMA
Signed-off-by: Simon Glass <sjg@chromium.org>
Diffstat (limited to 'README')
| -rw-r--r-- | README | 23 |
1 files changed, 0 insertions, 23 deletions
@@ -1723,29 +1723,6 @@ The following options need to be configured: the malloc area (as defined by CONFIG_SYS_MALLOC_LEN) should be at least 4MB. - CONFIG_LZMA - - If this option is set, support for lzma compressed - images is included. - - Note: The LZMA algorithm adds between 2 and 4KB of code and it - requires an amount of dynamic memory that is given by the - formula: - - (1846 + 768 << (lc + lp)) * sizeof(uint16) - - Where lc and lp stand for, respectively, Literal context bits - and Literal pos bits. - - This value is upper-bounded by 14MB in the worst case. Anyway, - for a ~4MB large kernel image, we have lc=3 and lp=0 for a - total amount of (1846 + 768 << (3 + 0)) * 2 = ~41KB... that is - a very small buffer. - - Use the lzmainfo tool to determinate the lc and lp values and - then calculate the amount of needed dynamic memory (ensuring - the appropriate CONFIG_SYS_MALLOC_LEN value). - CONFIG_LZO If this option is set, support for LZO compressed images |